Question

(-3,-2) equation quadratic

Answer 1

`(-3)^2+2*(-3)*(3-√(2)) +(11+6√(2))` = -2

Explanation:

Let x be -3

so that:

`x^(2) +2x k+k^2 = 9 - 6k + k^2`=-2

k being a constant.

if we do the quadratic equation, we get that:

`k_(1)=3-√(2);\\ k_(2)=3+√(2)`

at the end we get the following expression:

`(-3)^2+2*(-3)*(3-√(2)) +(11+6√(2))` = -2