Question

Calculate EC that makes with the base ABCD

Answer 1

Check the picture below.

`\tan(\theta )=\cfrac{\stackrel{opposite}{9}}{\underset{adjacent}{2.5}} \implies \tan^(-1)(~~\tan( \theta )~~) =\tan^(-1)\left( \cfrac{9}{2.5} \right) \\\\\\ \theta =\tan^(-1)\left( \cfrac{9}{2.5} \right)\implies \theta \approx 74.48^o`

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