Question

PLEASE HELP ASAP I DONT GET ITTTTTT

Answer 1

`2√(3x^2y)` ⇒
`x√(12y)`

`2x√(6xy^2)` ⇒
`y√(24x^3)`

`2y√(2x^4)` ⇒
`x^2√(8y^2)`

`3x^2√(2y^4)` ⇒
`xy√(18x^2y^2)`

Explanation:

Let's go in order and find the matching component:

1.
`2√(3x^2y)`

All the resulting bottom values have no coefficients in the outside of the root. So we can start by putting the coefficient inside.

`√(12x^2y)` , and one of the answers has 12 in them but the x on the outside which we can just get by sqaure rooting the
`x^2`. So, it will be
`x√(12y)`

2.
`2x√(6xy^2)`

Same thing, let's put the coefficient and variable inside.
`√(24x^3y^2)`. Now we can just square root the y and bring it outside the radical :
`y√(24x^3)`

3.
`2y√(2x^4)`

Let's do the same as the other two.
`√(8x^4y^2)`. Now square root the
`x^4` which is just
`x^2` and bring it outside the radical -->
`x^2√(8y^2)`

4.
`3x^2√(2y^4)`

Lastly, same thing again.
`√(18x^4y^4)`. They didn't completely simplify, however,
`xy√(18x^2y^2)` is equivalent.

That's it!