A pendulum is placed on a distant planet. The length is one meter, and the measured period is 1.4 seconds, what is the acceleration of gravity on that planet?

Question

asked Jul 28, 2022 208k views

1 Answer

Benjarobin · Answer 1 · 2022-08-02T01:20:02+0000

Answer:

$a=20.14\ m/s^2$

Step-by-step explanation:

The time period of the simple pendulum is given by :

$T=2\pi \sqrt{(l)/(g)}$

l is the length of the pendulum

g is the acceleration due to gravity

We have,

T = 1.4 s, l = 1 m

So,

$T^2=(4\pi^2 l)/(g)\\\\g= (4\pi^2 l)/(T^2)\\\\g= (4\pi^2 * 1)/((1.4)^2)\\\\g=20.14\ m/s^2$

So, the acceleration due to gravity of that planet is
$20.14\ m/s^2$ .