Question

A car traveling with an initial speed of 25 m/s decelerates at −5 m/s2 to a complete stop. What best approximates the distance the car travels during its deceleration?

Answer 1

The car travels approximately 62.5 meters during its deceleration.

Step-by-step explanation:

To calculate the distance the car travels during its deceleration, we can use the equation:

vf² = vi² + 2ad

where:

vf is the final velocity (which is 0 since the car comes to a complete stop), vi is the initial velocity (25 m/s), a is the deceleration (-5 m/s²), and d is the distance.

Plugging in the values, we have:

0² = (25)² + 2(-5)d

Simplifying, we get:

d = 625/10 = 62.5 m