Answer: Related What is 2+2+2+2+2+2+2×0+2? You will use PEMDAS for this problem. The order you will solve this is P(parentheses)E(exponents) M(ultiplication)/D(ivision)A(dd)/S(ubstract). First, since there are no parentheses are exponents, you can move onto multiplication or division. Multiplication is present, so you will multiple the 2 numbers being multiplied. 2+2+2+2+2+2+2×0+2 2×0 = 0 2+2+2+2+2+2+0+2 = 2+2+2+2+2+2+2 Next, you add or subtract. In this case, since all the numbers being added are the same, you can multiply the number of 2s there are by 2 as well. 2+2+2+2+2+2+2 = 14 OR 2×7 = 14 Therefore, your answer is: 14
Step-by-step explanation: You may choose any numbers in the domain of the function, but let's select some numbers that are easy to work with such as 1, 2, and 3.