Question

At a jeans factory, a random quality check found 8 pairs defective and 292 pairs with no problems. How many defective pairs can be excepted in the inventory of 3,000 pairs of jeans

Answer 1

8 + 292 = 8 out of 300 pairs were defective.

So:
`(8)/(300) = (x)/(3000)`

If we add a zero to both sides, then the answer would be that 80 pairs out of 3000 were defective.