Answer: Solution
verified
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(i) The concentration ratio is Q
c
=
[CH
3
COOH][C
2
H
5
OH]
[CH
3
COOC
2
H
5
][H
2
O]
(ii) The initial concentrations are
[CH
3
COOH]=1.00
[C
2
H
5
OH]=0.18
[CH
3
COC
2
H
4
]=0
[H
2
O]=0
The equilibrium concentrations are:
[CH
3
COOH]=
V
1−0.171
=
V
0.829
[C
2
H
5
OH]=
V
0.18−0.171
=
V
0.009
[CH
3
COC
2
H
4
]=
V
0.171
[H
2
O]=
V
0.171
The equilibrium constant expression is
K
c
=
[CH
3
COOH][C
2
H
5
OH]
[CH
3
COOC
2
H
5
][H
2
O]
=
V
0.829
×
V
0.009
V
0.171
×
V
0.171
=3.92
(iii) The initial concentrations are:
[CH
3
COOH]=1.00
[C
2
H
5
OH]=0.500
[CH
3
COC
2
H
4
]=0
[H
2
O]=0
The equilibrium concentrations are:
[CH
3
COOH]=
V
1−0.214
=
V
0.786
[C
2
H
5
OH]=
V
0.500−0.214
=
V
0.286
[CH
3
COC
2
H
4
]=
V
0.214
[H
2
O]=
V
0.214
The expression for the reaction quotient is:
Q
c
=
[CH
3
COOH][C
2
H
5
OH]
[CH
3
COOC
2
H
5
][H
2
O]
=
V
0.786
×
V
0.286
V
0.214
×
V
0.214
=0.204
As the value of the reaction quotient is not equal to the value of the equilibrium constant, the equilibrium is not yet achieved.
Step-by-step explanation: