Question

Write an equation of the line with a slope of 3/5 containing the point (5,-5).

Answer 1

`\displaystyle 3x - 5y = 40\:or\:y = (3)/(5)x - 8`

Explanation:

Plug all the information into the Slope-Intercept formula:

`\displaystyle y = ax + c`

−5 = ⅗[5] + c; −8 = c

3

`\displaystyle y = (3)/(5)x - 8`

If you were to plug the result into the Standard formula, do this:

y = ⅗x - 8

- ⅗x - ⅗x

_________

−⅗x + y = −8 [NO fractions, so multiply by the denominatour to eradicate them]

−5[−⅗x + y = −8] >>
`\displaystyle 3x - 5y = 40`

Now, you could leave the equation as
`\displaystyle -3x + 5y = -40,` but some teachers would prefer you eradicate the negative from the fraction as well.

I am joyous to assist you at any time.

Answer 2

y = 3/5x - 8

Explanation:

You can use another way but this is the way you were most likly taught.

y = mx + b

-5 = 3/5(5) + b

-8 = b

y = 3/5x - 8