Question

A 5 kg object has velocity of v(t) = 4t²+t. What is the force that acts on it at 2s?

Answer 1

Step-by-step explanation:

acceleration is rate of change of velocity

a=dv/dt =d/dt(4t^2+t) = 8t+1

Acceleration t=2 sec, =8(2)+1=17 m/s^2

Force = mass * acceleration = 5*17 = 85N