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Find the charge q(t) on the capacitor and the current i(t) in the given LRC-series circuit. L = 5 6 h, R = 10 Ω, C = 1 60 f, E(t) = 600 V, q(0) = 0 C, i(0) = 0 A q(t) = C i(t) = A Find the maximum charge on the capacitor. (Round your answer to three decimal places.) C

asked
User Chupik
by
8.6k points

1 Answer

2 votes

Answer:

7

Explanation:

1×7=7

(7%+8)=8.07

answered
User Jnovo
by
8.1k points
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