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What are the coordinates of(D0.25∘rx-axis)(ABCD) for A(2, 6), B(0, 0), C(-5, 8), and D(-2, 10)?

(express ordered pairs as decimal)

asked
User Mitghi
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7.9k points

1 Answer

2 votes

Answer: The coordinates of the image of a figure after a rotation of 0.25 degrees about the x-axis can be found using the following formulas:

x' = x

y' = y * cos(θ) - z * sin(θ)

z' = y * sin(θ) + z * cos(θ)

where (x, y, z) are the original coordinates and (x', y', z') are the new coordinates. In this case, we only need to find the y' coordinate because the rotation is about the x-axis and the x coordinate will not change.

For each point, we can use the formula to find the y' coordinate:

A (2, 6) -> y' = 6 * cos(0.25) - 0 * sin(0.25) = 5.99911... ~ 6

B (0, 0) -> y' = 0 * cos(0.25) - 0 * sin(0.25) = 0

C (-5, 8) -> y' = 8 * cos(0.25) - 0 * sin(0.25) = 7.99823... ~ 8

D (-2, 10) -> y' = 10 * cos(0.25) - 0 * sin(0.25) = 9.99649... ~ 10

So, the new coordinates after rotating 0.25 degrees about the x-axis are:

A (2, 6) -> (2, 6)

B (0, 0) -> (0, 0)

C (-5, 8) -> (-5, 8)

D (-2, 10) -> (-2, 10)

The coordinates of the points have not changed after the rotation because the rotation angle is very small.

Explanation:

answered
User Jmonsky
by
8.4k points
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