Question

Prove that (n-5) squared - (n-3) squared is a multiple of 4

Answer 1

Explanation:

`(n-5)^(2) -(n-3)^(2) =n^(2) -10n+25-n^(2) +6n-9=-4n+16=-4(n-4)\\`

if you divide it with 4

you'll get -(n-4)=4-n