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What mass of iron(II) sulfate would be needed to provide 28 grams of iron?

What mass of iron(II) sulfate would be needed to provide 28 grams of iron?
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What mass of iron(II) sulfate would be needed to provide 28 grams of iron?

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User Michael Dubakov
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Answer:

Step-by-step explanation:

one half mole or 76 grams of Iron (II) Sulfate.

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User Theo Kouzelis
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