Question

Consider the reaction and the rate law below.

2O3 → 302
R= k[03]2

What is the overall order of the reactants in this rate law?

A. 0
B. 1
C. 2
D. 3​

Answer 1

The overall order of the reactants in this rate law : 2

Further explanation

Given

Reaction

2O3 → 302

The rate law :

R= k[03]²

Required

The overall order

Solution

The overall order : the sum of orders for each reactant

For A + B ---> C + D

r = k [A]ᵃ[B]ᵇ

The overall reaction order is m+n

So for the rate law of R= k[03]², the overall order = 2