Question

avid has a bag of coins. The bag contains 9 dimes, 4 nickels, and 3 pennies. He will randomly select 2 coins from the bag one at a time without replacement. What is the probability that David will select a nickel first and then a dime.

Answer 1

Answer: 1/4.

Explanation:

The probability of selecting a nickel first and then a dime is calculated as follows:

Step 1: Determine the number of successful outcomes. There are 4 nickels and 9 dimes in the bag, so there are 4 successful outcomes of selecting a nickel first.

Step 2: Determine the number of possible outcomes. Since David is selecting 2 coins from the bag one at a time without replacement, the number of possible outcomes is 16 (9 + 4 + 3).

Step 3: Calculate the probability. The probability of selecting a nickel first and then a dime is 4/16 = 1/4.

So, the probability that David will select a nickel first and then a dime is 1/4.