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203,199,195 find the 35th term

1 Answer

1 vote

Answer:

67

Explanation:

The given arithmetic sequence is,

203, 199, 195,......

In the sequence, the first time a = 203,

And common difference of the sequence d = -4

Formula for nth term of the sequence,

aₙ = a + (n-1) . d

To find 35th term of the sequence, substitute n= 35,

a₃₅ = 203 + (35-1).(-4)

= 203 + 34x-4

= 203 - 136

= 67

©Thank You

Answered By Solution 49

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