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A line passes through the point (6,-1) and has a slope of m=0 Write an equation for the line in point-slope form

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Answer:

The proper linear equation is written in following form: y = mx + b (where m is slope, and b is y-intercept). Since we already have the slope, we need to find the y-intercept, b

So we plug in what we have:

y = mx + b

-1 = (-3)(6) + b, where we solve for b

-1 = -18 + b

b = 17

Finally, the equation of the line that passes through point (6, -1) and has a slope of -3 is y = -3x + 17

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