Question

We have a basket which contains 6 white balls, 3 red balls and 12 yellow balls. Now,

we take out one ball from this basket. What is the probability of this ball being either red
or yellow?

Answer 1

The probability of the ball being red is 3/21 and the probability of the ball being yellow is 12/21. To find the probability of the ball being either red or yellow, we add the probabilities of each event: (3/21) + (12/21) = 15/21 or approximately 0.71.

Answer 2

There are a total of 6 + 3 + 12 = 21 balls in the basket.

Out of which 3 are red and 12 are yellow.

So, the probability of getting a red ball is 3/21 and the probability of getting a yellow ball is 12/21.

To find the probability of getting either red or yellow we need to add these two probabilities.

So, the probability of getting either a red or yellow ball is (3/21) + (12/21) = 15/21

This can be simplified as 0.71 or 71%. So, the probability of getting either a red or yellow ball is 71%.