Question

Solve each equation
1/14(3x-2)=x+10/10

Answer 1

`(1)/(14)(3x-2)=(x+10)/(10) \ \ / \cdot 140\\\\140\cdot (1)/(14)(3x-2)=140\cdot(x+10)/(10)\\ \\10(3x-2)=14(x+10)\\\\30x-20 =14x+140\\\\30x-14x=140+20\\ \\16x=160 \ \ /:16\\ \\x=10`

Answer 2

`(1)/(14)(3x-2)=(x+10)/(10)\ \ \ \ \ |multiply\ both\ sides\ by\ 140\\\\10(3x-2)=14(x+10)\\\\30x-20=14x+140\\\\30x-14x=140+20\\\\16x=160\\\\x=160:16\\\\\boxed{x=10}`