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If (-2, y) lies on the graph of y =4^x, then y =

1 Answer

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Simply plug in x= -2 in to y = 4^x, and solve for y.


y=4^(-2)\\\\y = (1)/(4^2)\\\\\boxed{\bf{y=(1)/(16)}}

So, the point (-2, ¹/₁₆) lies on the graph of y = 4^x.

Your final answer is y = ¹/₁₆.
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