Question

What is the sum of all the integers between the square root of 10 and the square root of 47

Answer 1

What's the square root of 10 ?
3²=9 and 4²=16
So √10 is somewhere between 3 and 4 .

What's the square root of 47 ?
6²=36 and 7²=49
So √47 is somewhere between 6 and 7 .

The integers between √10 and √47 are 4, 5, and 6 .

Their sum is (4 + 5 + 6) = 15 .

Answer 2

First estimate the square root of 10, about 3.16
and then the square root of 47, about 6.85
now what are the integers in between 3.16 and 6.85:
4,5,6
now add them all
4+5+6
=15
Hope this helps.