Question

What is the total amount of work required to

move a proton through a potential difference of
100. volts?
(1) 1.60 × 10^–21 J (3) 1.00 × 10^2 J
(2) 1.60 × 10^–17 J (4) 6.25 × 10^20 J

Answer 1

Number 2

Step-by-step explanation:

Elementary Charge x volts given

Answer 2

`W = 1.6 * 10^(-17) J`

Step-by-step explanation:

Work done to move a charge through a given potential difference is

`W = q(\Delta V)`

here

q = magnitude of charge

`\Delta V` = potential difference

here it is given that charge of the particle is same as charge of proton

`q = 1.6 * 10^(-19) C`

`\Delta V = 100 V`

now we have

`W = (1.6 * 10^(-19)) (100)`

`W = 1.6 * 10^(-17) J`