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4 votes
Let f(x)=2x-3 and g(x)= -x^2-1 find ( g o f) (x)

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User Skaue
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2 Answers

3 votes

g \circ f=-(2x-3)^2-1=-(4x^2-12x+9)-1=\\ =-4x^2+12x-9-1=-4x^2+12x-10\\
answered
User Ruchir Gupta
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8.0k points
7 votes

f(x)=2x-3\ \ \ and\ \ \ g(x)= -x^2-1\\\\( g \circ f) (x)=g\bigg(f(x)\bigg)=g\bigg(2x-3\bigg)=-(2x-3)^2-1=\\\\=-(4x^2-12x+9)-1=-4x^2+12x-9-1=-4x^2+12x-10
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User Cian
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