Question

How many moles of 2 are required to prepare 2.00 litters of 0.700m CaCl2

Answer 1

Answer:1.4 moles of calcium chloride are required.

Step-by-step explanation:

Molarity of the calcium chloride solution = 0.700 M = 0.700 mol/L

Volume of the solution = 2 L

Moles of the calcium chloride = x

`Molarity=\frac{\text{moles of the substance}}{\text{volume of the Solution (L)}}`

`0.700 mol/L=(x)/(2 L)`

x = 1.4 moles of calcium chloride

1.4 moles of calcium chloride are required.