asked 114k views
2 votes
Find dy/dx
2x+3y=sinx

1 Answer

4 votes

2x+3y=sinx\\\\3y=sinx-2x\ \ \ \ /:3\\\\y=(1)/(3)(sinx-2x)\\\\(\delta y)/(\delta x)=\left[(1)/(3)(sinx-2x)\right]'=(1)/(3)\left[(sinx)'-(2x)'\right]=(1)/(3)(cosx-2)
answered
User Alberto Acepsut
by
8.5k points
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