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If a chemist analyzes a 3.84g sample containing sand and table sugar, and recovers 1.43g of      sand, what  percent by mass of table sugar should the chemist report for this sample.

asked
User Octern
by
8.4k points

2 Answers

3 votes


well you would use the formula, which is,

mass percent= g of solute/ g of solute+ of solvent

and then you multiply by 100.....so when I did it I did 1.43/3.84+1.43 and multiplied it by 100 giving me 27%

answered
User Aprovent
by
8.3k points
2 votes
3.84 - 1.43 = 2.41
2.41g of table sugar

% mass = ( (mass of element) / (total mass) ) * 100
% mass = (2.41 / 3.84) * 100
% mass = (0.6276) * 100
% mass = 62.76

62.76%
answered
User Vasily Kabunov
by
7.4k points
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