asked 84.5k views
0 votes
The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release 235.0 kJ of energy?

2 Answers

0 votes
1 mole of gold = 197g

12.550 kJ-------------- 197g Au
235.0 kJ--------------------x
x = 3,69g Au

answer: 3,69g Au
4 votes

Answer;3.67061 kg of gold must be solidified to release 235 kJ of energy.

Step-by-step explanation:

Molar heat of gold = 12.550 kJ/mol

1 mole of gold releases = 12.550 kJ/mol

Or we can rewrite it as ,1 kJ of energy is given by
[(1)/(12.550) mol

Then 235 kJ of energy will be released by:


(1)/(12.550 kJ)* 235 kJ=18.72 moles of gold

Mass of gold in 18.72 moles = 18.72 mole × 196.08 g/mol =3,670.61 g =3.67061 kg

1 kg = 1000 g

3.67061 kg of gold must be solidified to release 235 kJ of energy.

answered
User Brian Beech
by
8.1k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.