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Write an equation of a line parallel to y=2/3x-1 that contains the point (6,-2)

1 Answer

2 votes
y - y₁ = m(x - x₁)
y - (-2) = ²/₃(x - 6)
y + 2 = ²/₃(x) - ²/₃(6)
y + 2 = ²/₃x - 4
- 2 - 2
y = ²/₃x - 6
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User Manu R S
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