Question

X^2-6x+4=0
Please explain how to do quadratic formula with this problem.

Answer 1

`x^(2) - 6x + 4 = 0`

`\frac{-(-6) \± \sqrt{-(-6)^(2) - 4(1)(4)}}{2(1)}`

`(6 \± √(36 - 16))/(2)`

`(6 \± √(20))/(2)`

`(6 \± 2√(5))/(2)`

`3 \± √(5)`

`3 + √(5)`
`or`
`3 - √(5)`