Question

Five times the sum of a number and two is thirty-five. Find the number.

Answer 1

`n-a\ number\\\\5(n+2)=35\ \ \ \ |divide\ both\ sides\ by\ 5\\\\(n+2)=7\\\\n+2=7\ \ \ \ |subtract\ 2\ from\ both\ sides\\\\\huge\boxed{n=5}`

Answer 2

Let the missing number be 'x'


`\sf 5 (x + 2 ) = 35 \\ \\ Distribute \ (5) (x) + (5) (2) = 35 \\ \\ 5x + 10 = 35 \\ \\ Subtract \ 10 \ from \ both \ sides. \\ \\ 5x + 10 - 10 = 35- 10 \\ \\ 5x = 25 \\ \\ Divide \ both \ sides \ by \ 5. \\ \\ (5x)/(5) = (25)/(5) \\ \\ x = 5`