Question

Four children have small toys. The first child has 1/10 of the toys, the second child has 12 more toys than the first, the third child has one more toy of what the first child has and the fourth child has double the third child. How many toys are there?

Answer 1

Call x the amount of toys the first child has. We write the equation x+(x+12)+(x+1)+2(x+1)=10x. This is equal to 5x+15=10x. Subtracting 5x, we see that 5x=15, so x=3. There are 10x toys, so we have 3*10=30 total toys.