Question

Identify the 12th term of a geometric sequence where a1 = 8 and a6 = -8,192. 134,217,728 33,554,432 -33,554,432 -134,217,728

Answer 1

-33,554,432.

Explanation:

I just took the test and it is correct

Answer 2

`a_1=8 \\ a_6=-8192 \\ \\ a_n=a_1 * r^(n-1) \\ -8192=8 * r^(6-1) \\ (-8192)/(8)=r^5 \\ -1024=r^5 \\ \sqrt[5]{-1024}=r \\ r=-4 \\ \\ a_(12)=8 * (-4)^(12-1)=8 * (-4)^(11)=8 * (-4194304)=-33554432`

The 12th term of the sequence is -33,554,432.