How many milliliters of a 3.0 M HCl solution are required to make 250.0 milliliters of 1.2 M HCl?

asked Dec 23, 2016 142k views

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4 votes

M1V1=M2V2
(3)(V1)=(250)(1.2)
V1=100 mL

Erik Noren answered Dec 24, 2016

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The formula to use is M₁V₁=M₂V₂
We are trying to find V₁ so V₁=M₂V₂/M₁
=250X1.2 /3
=100mL

Atcold answered Dec 28, 2016

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