Question

Using the quadratic formula to solve 2x^2 = 4x – 7, what are the values of x?

Answer 1

Is C.

Ccccccccccccccc

Answer 2

For this case we have the following quadratic equation:

`2x ^ 2 = 4x - 7`

Rewriting the equation we have:

`2x ^ 2 - 4x + 7 = 0`

From here, we have:

`a=2 b = -4c = 7`

Substituting values in the quadratic equation we have:

`x = (-b+/-√(b^2-4ac))/(2a)`

`x = (-(-4)+/-√((-4)^2-4(2)(7)))/(2(2))`

Rewriting the equation we have:

`x = (4+/-√(16-56))/(4)`

`x = (4+/-√(-40))/(4)`

`x = (4+/-√(-4*10))/(4)`

`x = (4+/-2i√(*10))/(4)`

`x = (2+/-i√(*10))/(2)`

Answer:

The values of x are given by:

`x = (2+i√(*10))/(2)`

`x = (2-i√(*10))/(2)`