Question

line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to line AB ?

Answer 1

Since the line is parallel to AB, the two slopes are the same

slope of AB = m = (y₂-y₁)/(x₂-x₁)

m= (5-0)/(-6-(-3))= - 5/3
The equation of the line is y-y₁=m(x-x₁)
The origin P(0,0)
y=mx
y= -
`(5)/(3)`x Solution