Question

What is the mean absolute deviation for the data?

20, 25, 30, 30, 45

A.
5

B.
6

C.
10

D.
25

Answer 1

`\overline{x}-arithmetic\ mean\\\\\overline{x}=(20+25+30+30+45)/(5)=(150)/(5)=30\\\\the\ mean\ absolute\ deviation:\delta=\frac{|x_1-\overline{x}|+|x_2-\overline{x}|+|x_3-\overline{x}|+...+|x_n-\overline{x}|}{n}\\\\\delta=(|20-30|+|25-30|+|30-30|+|30-30|+|45-30|)/(5)=(|-10|+|-5|+|0|+|0|+|15|)/(5)\\\\=(10+5+0+0+15)/(5)=(30)/(5)=\boxed{6}\leftarrow answer`