Question

How do you solve 5v/13=25/39

Answer 1

Solving a Single Variable Equation :

2.3 Solve : 3v-5 = 0

Add 5 to both sides of the equation :
3v = 5
Divide both sides of the equation by 3:
v = 5/3 = 1.667

One solution was found : v = 5/3 = 1.667
Making Equivalent Fractions : 1.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respectiveMultiplier. L. Mult. • L. Num. 5v • 3 —————————————————— = —————— L.C.M 39 R. Mult. • R. Num. 25 —————————————————— = —— L.C.M 39Calculating the Least Common Multiple : 1.1 Find the Least Common Multiple

The left denominator is : 13

The right denominator is : 39
Number of times each prime factor
appears in the factorization of: Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right} 131113011 Product of all
Prime Factors 133939
Least Common Multiple:
39 v = 5/3 = 1.667 next



rearrange = 5*v/13-(25/39)=0

Step by step solution:part 1: 5v 25 Simplify —— - —— 13 39

Calculating Multipliers : 1.2 Calculate multipliers for the two fractions


Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 3

Right_M = L.C.M / R_Deno = 1

Pulling out like terms : 1.5 Pull out like factors :

15v - 25 = 5 • (3v - 5)
Equation at the end of step 1 : 5 • (3v - 5) ———————————— = 0 39
Step 2 : 5•(3v-5) Solve ———————— = 0 39