How do you solve x^(2) -8x=65 is it (x-4)^2-81

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asked Mar 25, 2016 48.9k views

1 Answer

Doug Mead · Answer 1 · 2016-03-29T10:32:55+0000

x² - 8x = 65
x² - 8x + 16 = 65
x² - 8x + 16 - 65 = 65 - 65
x² - 4x - 4x + 16 - 65 = 0
x(x) - x(4) - 4(x) + 4(4) - 65 = 0
x(x - 4) - 4(x - 4) - 65 = 0
(x - 4)(x - 4) - 65 = 0
(x - 4)² - 65 = 0

It is actually (x - 4)² - 65.

How do you solve x^(2) -8x=65 is it (x-4)^2-81

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