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Solve with quadratic formula 8x^2-9x-5=0

asked
User ReneS
by
8.2k points

1 Answer

3 votes

8x^(2) - 9x - 5 = 0


x = \frac{-(-9) +/- \sqrt{(-9)^(2) - 4(8)(-5)}}{2(8)}


x = (9 +/- √(81 + 160))/(16)


x = (9 +/- √(241))/(16)


x = (9 +/- 15.524)/(16)


x = 0.5625 +/- 0.97025

x = 0.5625 + 0.97025
x = 0.5625 - 0.97025

x = 1.53275
x = -0.40775
answered
User Anthony Perez
by
8.5k points

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