Question

Find The Algebraic Inverse.
f(x)=15x-1

Answer 1

We want a function
`g` such that
`g(15x-1)=x`

One easy way to do to that is to choose
`g(x)=(x+1)/(15)`

That function works :
`g(15x-1)=(15x-1+1)/(15)=x`

Due to the uniqueness of the inverse, this is the function we were searching for.

Answer 2

`f(x)=15x-1\to y=15x-1\\\\15x-1=y\ \ \ \ |add\ 1\ to\ both\ sides\\\\15x=y+1\ \ \ \ \ |divide\ both\ sides\ by\ 15\\\\\boxed{x=(y)/(15)+(1)/(15)}\to\boxed{x=(1)/(15)y+(1)/(15)}\\\\Answer:\boxed{\boxed{[f(x)]^(-1)=(1)/(15)x+(1)/(15)}}`