Question

The molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?

Answer 1

Answer : The moles of
`LiOH` needed are, 1.158 moles

Explanation : Given,

Mass of
`CO_2` = 25.5 g

Molar mass of
`CO_2` = 44.01 g/mole

First we have to calculate the moles of
`CO_2`.

`\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}=(25.5g)/(44.01g/mole)=0.579moles`

Now we have to calculate the moles of
`LiOH`

The balanced chemical reaction will be,

`2LiOH+CO_2\rightarrow Li_2CO_3+H_2O`

From the balanced chemical reaction we conclude that,

As, 1 mole of
`CO_2` react with 2 moles of
`LiOH`

So, 0.579 mole of
`CO_2` react with
`2* 0.579=1.158` moles of
`LiOH`

Therefore, the moles of
`LiOH` needed are, 1.158 moles

Answer 2

The chemical reaction would be as follows:
2LiOH + CO2 = Li2CO3 + H2O

We are given the amount of the CO2 to be used in the reaction. We use this to calculate the amount of LiOH. We do as follows:

25.5 g CO2 ( 1 mol / 44.01 g ) ( 2 mol LiOH/1 mol CO2) = 1.16 mol LiOH needed