How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction? 6Li + N₂ 2Li₃N 0.013 moles 0.04 moles 0.08 moles 0.16 moles 0.48 moles

Question

asked Jul 2, 2017 147k views

1 Answer

Danieljames · Answer 1 · 2017-07-08T18:40:11+0000

Each mole of N₂ generates 2 moles of Li₃N. Thus,
0.08 moles of Li₃N will require:
0.08 / 2
= 0.04 moles of N₂

The second option is correct.