asked 17.8k views
2 votes
PQ←→ is constructed by making arcs centered at A and B without changing the compass width. Which equation is not necessarily true?

PQ = AB

AP = PB

AQ = BQ

AR = RB

PQ←→ is constructed by making arcs centered at A and B without changing the compass-example-1
asked
User Nicomak
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7.8k points

2 Answers

5 votes

Answer with explanation:

PQ is Perpendicular Bisector of Line Segment AB.

The Perpendicular Bisector of any line segment can be drawn by, opening the compass more than half, by putting the nib of compass at one end of line segment and marking arc on both side of line segment from both the ends of Segment.

The following Property that the perpendicular bisector PQ follows when it bisects the line segment AB.

1. AP=BP

2. A Q=B Q

3. AR=BR

4. ∠ARP=∠BRP=∠ARQ=∠BRQ=90°

Option 1 : PQ=AB, the length of two segments is not necessary that , it may be equal, is false Statement about the perpendicular bisector PQ.

answered
User Mehraj Malik
by
8.0k points
2 votes
The equation is not necessarily true is PQ = AB
answered
User Elliott Brossard
by
8.4k points
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