Log(x+3)(2x+3)+log(x+3)(x+5)=2

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asked Nov 28, 2016 79.6k views

1 Answer

Antonio Narkevich · Answer 1 · 2016-12-05T08:38:04+0000

log(x-3)+log(x) = 2 + log(x+2)
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log[(x-3)x] - log(x+2) = 2
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log[(x^2-3x)/(x+2)] = 2
----
(x^2-3x)/(x+2) = 2^2
-------

x^2-3x = 4x+8
x^2 - 7x - 8 = 0
Factor:
(x-8)(x+1) = 0
Positive solution:
x = 8

Log(x+3)(2x+3)+log(x+3)(x+5)=2

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