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Alexandra has 36 coins valued at $6.00. She has only nickels and quarters. Which equation can be used to solve for the number of nickels, n? 0.05n + 0.25(36 – n) = 6 0.05n + 0.2…
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Alexandra has 36 coins valued at $6.00. She has only nickels and quarters. Which equation can be used to solve for the number of nickels, n? 0.05n + 0.25(36 – n) = 6 0.05n + 0.2…
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Jan 3, 2017
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Alexandra has 36 coins valued at $6.00. She has only nickels and quarters. Which equation can be used to solve for the number of nickels, n?
0.05n + 0.25(36 – n) = 6
0.05n + 0.25(36 – n) = 36
n + 0.05 = 0.05n
n + (36 – n) = 36
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Answer:
The answer is going to be 0.05n + 0.25(36-n) = 6
Step-by-step explanation:
Daveilers
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Jan 4, 2017
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Let n be the number of nickels and q be the number of quarters, then
n + q = 36 . . . (1)
0.05n + 0.25q = 6 . . . (2)
From (1): q = 36 - n . . . (3)
Putting (3) into (2) gives:
0.05n + 0.25(36 - n) = 6
Markus Lanthaler
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Jan 8, 2017
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