asked 45.8k views
1 vote
A spring is stretched 2.0 cm. If the same spring is stretched 8.0 cm the ratio of the second and first potential energies of the spring is

16
9
4
1

1 Answer

3 votes
potential energy of spring equals K times X squared divided by 2 where X is displacement

4 times squared equals 16

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User Kapreski
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