Question

What is the ratio of the area of the inner square to the area of the outer square?

(a−b)²+b²/a²

a²−b²/a²

(a−b)²/(a+b)²

(ab)²/(a+b)²

Answer 1

Answer: I just did the quiz in Plato the answer will be option A or (a-b) 2+b2/a2

Explanation:

Answer 2

the answer is
(a−b)²+b²/a²


proof

if A is the area of the
inner squared, so A= c², and c²= (a−b)²+b²

so the side of the outer must be a-b +b=a, its area is a²