Question

NiCl3 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.600 M NiCl3 solution.

Answer 1

Answer : The concentration of each of the individual ions are, 0.6 M
`Ni^(3+)` and 1.8 M
`Cl^-`.

Explanation : Given,

Concentration of
`NiCl_3` solution = 0.6 M

The balanced chemical reaction will be :

`NiCl_3\rightarrow Ni^(3+)+3Cl^-`

From the balanced chemical reaction we conclude that, 1 mole of
`NiCl_3` dissociates to give 1 mole of
`Ni^(3+)` and 3 moles of
`Cl^-`.

So,

The concentration of
`Ni^(3+)` = The concentration of
`NiCl_3` = 0.6 M

The concentration of
`Cl^-` = 3 × The concentration of
`NiCl_3` =
`3* 0.6M=1.8M`

Therefore, the concentration of each of the individual ions are, 0.6 M
`Ni^(3+)` and 1.8 M
`Cl^-`.

Answer 2

For the answer to the question above, I'll show the solutions for my answer.
(0.800 M NiCl3) x (1 mol Ni^3+ / 1 mol NiCl3) = 0.800 M Ni^3+
(0.800 M NiCl3) x (3 mol Cl^- / 1 mol NiCl3) = 2.40 M Cl^-
I hope my answer helped you. Have a nice day!