Question

A polygon has an interior angle sum of 3060° how many sides must the polygon have?

Answer 1

3060÷180 +2

using the formula (n-2) × 180 = sums of interior angles

Answer 2

sum of interior angles=(n-2)180
3060=(n-2)180
3060/180=n-2
17=n-2
n=17+2
n=19..